3n^2-90.5=0

Solution for 3n^2-90.5=0 equation:

3n^2-90.5=0

a = 3; b = 0; c = -90.5;
Δ = b2-4ac
Δ = 02-4·3·(-90.5)
Δ = 1086
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1086}}{2*3}=\frac{0-\sqrt{1086}}{6}
=-\frac{\sqrt{}}{6}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1086}}{2*3}=\frac{0+\sqrt{1086}}{6}
=\frac{\sqrt{}}{6}
$